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Set adb vendor keys

由 99封情书 提交于 2019-11-26 17:41:49
问题 EDIT: I figured out the problem, i think. ADB found out I wasn't on the latest updates (at&t released a stagefright udpate and i didnt know) so ADB didn't let me debug. Everything is fine now. I have been debugging my app on an AT&T HTC One M8 for about a month. Suddenly today when I plugged in my phone, I didn't get the authorization popup. After an hour of troubleshooting, I found the problem, but not a solution. This is the error i get in Android Studio 1.3.1: device unauthorized. This

Difference between movq and movabsq in x86-64

由 ╄→尐↘猪︶ㄣ 提交于 2019-11-26 16:44:58
I'm a newcomer here and just starting to study assembly language. So please correct me if I'm wrong, or if this post doesn't make any sense I will delete. I'm talking about data movement instructions in the x86-64 Intel architecture. I have read that the regular movq instruction can only have immediate source operands that can be represented as 32-bit two's complement numbers, while the movabsq instruction can have an arbitrary 64-bit immediate value as its source operand and can only have a register as a destination. Could you please elaborate on this? Does that mean I can move 64-bit

How does “mov (%ebx,%eax,4),%eax” work? [duplicate]

由 无人久伴 提交于 2019-11-26 14:48:50
问题 This question already has answers here : What is the meaning of MOV (%r11,%r12,1), %edx? (2 answers) Closed 2 years ago . Been working on an assembly assignment, and for the most part I understand assembly pretty well. Or well at least well enough for this assignment. But this mov statement is tripping me up. I would really appreciate if someone could just explain how this mov statement is manipulating the register values. mov (%ebx,%eax,4),%eax P.S. I wasnt able to find this specific type of

What does the bracket in `movl (%eax), %eax` mean?

由 允我心安 提交于 2019-11-26 14:17:05
问题 I have googled enough but could not figure out what the bracket () means. Also, I see some syntax as movl 8(%ebp), %eax Could some someone suggest me some good reference? I have not been able to find any in the top 20 results from Google. 回答1: %eax is register EAX; (%eax) is the memory location whose address is contained in the register EAX; 8(%eax) is the memory location whose address is the value of EAX plus 8. 回答2: http://web.archive.org/web/20080215230650/http://sig9.com/articles/att

What is the meaning of MOV (%r11,%r12,1), %edx?

由 对着背影说爱祢 提交于 2019-11-26 12:32:51
问题 What does this instruction do? mov (%r11,%r12,1), %edx 回答1: Look here. It says In the AT&T Syntax, memory is referenced in the following way, segment-override:signed-offset(base,index,scale) Down on the page there are some examples. I find this the best: GAS memory operand NASM memory operand ------------------ ------------------- (%ecx,%ebx,2) [ecx+ebx*2] mov source, destination in AT&T syntax copies the value from source to destination. Also consider the size of edx. How many bytes (4) do

what is the order of source operands in AT&T syntax compared to Intel syntax?

由 故事扮演 提交于 2019-11-26 10:00:26
问题 The Intel ISA reference documentation for this instruction is clear: VPBLENDVB xmm1, xmm2, xmm3/m128, xmm4 Select byte values from xmm2 and xmm3/m128 using mask bits in the specified mask register, xmm4 , and store the values into xmm1 . xmm1 is the destination, xmm2/3/4 are source operands So what does this become using AT&T syntax? We know that the destination register must be last, but what is the order of source operands? vpblendvb $xmm2, $xmm3, $xmm4, $xmm1 or vpblendvb $xmm4, $xmm3,

What does cltq do in assembly?

由 烂漫一生 提交于 2019-11-26 06:47:55
问题 0x0000000000400553 <main+59>: mov -0x4(%rbp),%eax 0x0000000000400556 <main+62>: cltq 0x0000000000400558 <main+64>: shl $0x3,%rax 0x000000000040055c <main+68>: mov %rax,%rdx In fact my programe is as simple as : 5 int main(int argc, char *argv[]) { 6 int i = 0; 7 while(environ[i]) { 8 printf(\"%s\\n\", environ[i++]); 9 } 10 return 0; But the assembly output is pretty long: Dump of assembler code for function main: 0x0000000000400518 <main+0>: push %rbp 0x0000000000400519 <main+1>: mov %rsp,

Difference between movq and movabsq in x86-64

由 陌路散爱 提交于 2019-11-26 04:54:39
问题 I\'m a newcomer here and just starting to study assembly language. So please correct me if I\'m wrong, or if this post doesn\'t make any sense I will delete. I\'m talking about data movement instructions in the x86-64 Intel architecture. I have read that the regular movq instruction can only have immediate source operands that can be represented as 32-bit two\'s complement numbers, while the movabsq instruction can have an arbitrary 64-bit immediate value as its source operand and can only

Assembling 32-bit binaries on a 64-bit system (GNU toolchain)

由 六月ゝ 毕业季﹏ 提交于 2019-11-25 22:22:54
问题 I write the assembly code that can be compiled: as power.s -o power.o there is on problem when I link the power.o object file: ld power.o -o power In order to run on the 64bit OS (Ubuntu 14.04), I added .code32 at the beginning of the power.s file, however I still get error: Segmentation fault (core dumped) power.s : .code32 .section .data .section .text .global _start _start: pushl $3 pushl $2 call power addl $8, %esp pushl %eax pushl $2 pushl $5 call power addl $8, %esp popl %ebx addl %eax,
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