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可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How do I add value to a woocommerce attribute through code? I have created an attribute called 'Dispatch time' (taxonomy: pa_dispatch) and now I want to add value to a particular product's Dispatch attribute. How to do this programmatically? 回答1: I found the answer, you need to use wp_set_object_terms to set the terms of object of a taxonomy, wp_set_object_terms( $object_id, $terms, $taxonomy, $append); Where, $append can be true or false , if true, the tag will be appended to existing tag, if false, the tag is replaced. In my example, wp

I have a program that is supposed to either add or subtract two hardcoded numbers based on user input 0 or not 0 . I get memory access violation error inside input . when i try to call sum or call diff instead input in line 9 it works fine and gives me expected output. loop and next is used to display result from stack. .text .global _start _start: xorl %esi, %esi # zerowanie licznika call input # <---- line 9 loop: # label movl $0, %edx # reszta z dzielenia movl $10, %ebx # dzielnik divl %ebx # dzielenie, wynik w eax, reszta w edx addl $48, %edx # kod ASCII pushl %edx # edx na stos incl %esi

I've spent 2 hours googling, but to no avail --- there are not many beginner-level guides for assembly, and the course I am taking right now dos not do a very good job at explaining some stuff. Anyway; I've been trying to work with SSE and tried comparing two double s using comisd instruction. I've spent a lot of time to understand how to hard-code a non-integer constant (let's call it example , it is declared as example: .long 3794832442 .long 1044740494 ); but after I've done that, I couldn't get it to work --- "operand type mismatch". I've turned to C-to-assembly translator and found out

I've written a solo program just to figure out how to do this, earlier I added 48 to the number to print but now when I get numbers larger than 9 it's not really sufficient any more. So the following program should put 23 into the my temp, compares 23 to 10 if it's smaller than 10 I can print otherwise put the temp away in rax, put 10 in r11 and divide 23 by 10. Put the result from rax in temp and check again. I still need to add a way to retrieve the earlier numbers but first thing first. Have I missunderstood what happens, the result I get is float number error #include <stdio.h> #Inkludera

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I have a question regarding how to initialize an array in assembly. I tried: .bss #the array unsigned: .skip 10000 .data #these are the values that I want to put in the array par4: .quad 500 par5: .quad 10 par6: .quad 15 That's how I declared my string and the variables that I want to put it inside. This is how I tried to put them into the array: movq $0 , %r8 movq par4 , %rax movq %rax , unsigned(%r8) incq %r8 movq par5 , %rax movq %rax , unsigned(%r8) incq %r8 movq par6 , %rax movq %rax , unsigned(%r8) I tried printing the elements to check if everything is okay, and only the last one prints