assert | 易学教程

Should I be using assert in my PHP code?

阅读更多关于 Should I be using assert in my PHP code?

问题 A coworker has added the assert command a few times within our libraries in places where I would have used an if statement and thrown an exception. (I had never even heard of assert before this.) Here is an example of how he used it: assert('isset($this->records); /* Records must be set before this is called. */'); I would have done: if (!isset($this->records)) { throw new Exception('Records must be set before this is called'); } From reading the PHP docs on assert, it looks like it's

How do I use Assert to verify that an exception has been thrown?

阅读更多关于 How do I use Assert to verify that an exception has been thrown?

How do I use Assert (or other Test class?) to verify that an exception has been thrown? For "Visual Studio Team Test" it appears you apply the ExpectedException attribute to the test's method. Sample from the documentation here: A Unit Testing Walkthrough with Visual Studio Team Test [TestMethod] [ExpectedException(typeof(ArgumentException), "A userId of null was inappropriately allowed.")] public void NullUserIdInConstructor() { LogonInfo logonInfo = new LogonInfo(null, "P@ss0word"); } ojrac Usually your testing framework will have an answer for this. But if it's not flexible enough, you can

[导入]小心Assert

阅读更多关于 [导入]小心Assert

　　今天弄弯管机的破程序的时候，突然发现DEBUG模式和RELEASE模式下面得到的值不同，很是疑惑于这些微妙的差别，以为是RELEASE模式的优化出了问题。但对比DEBUG和RELEASE，即便将几乎所有编译选项都调整为一样，也不能得出一样的结果。　　后来进行了跟踪调试，以外的发现assert(oneFunction())这句竟然在RELEASE模式下面不执行。哦，我当时使用这个assert是为了断言一个函数的返回值为正，而这个函数正好要影响我的数据。当然assert在DEBUG模式下面没有问题，正常的编译运行成功。但在RELEASE模式下面一旦调试到这个assert的上一行，在进行单步跟踪的时候就跳到了assert的下一行。也就是说这个函数根本没有运行。原因就出现在这里。把assert去掉以后，函数就正常运行了。　　以后用assert要多加小心了，assert函数返回值的时候也一定要把返回值先赋值给一个变量，再assert，就不会出现这样的问题了。文章来源: http://www.hesicong.net/pjblog/default.asp?id=294 转载于:https://www.cnblogs.com/hesicong/archive/2007/11/08/962507.html 来源： https://blog.csdn.net/weixin_30538029

Ways to ASSERT expressions at build time in C

阅读更多关于 Ways to ASSERT expressions at build time in C

I'm tidying up some older code that uses 'magic numbers' all over the place to set hardware registers, and I would like to use constants instead of these numbers to make the code somewhat more expressive (in fact they will map to the names/values used to document the registers). However, I'm concerned that with the volume of changes I might break the magic numbers. Here is a simplified example (the register set is more complex): const short mode0 = 0; const short mode1 = 1; const short mode2 = 2; const short state0 = 0; const short state1 = 4; const short state2 = 8; so instead of : set

python中assert的用法

阅读更多关于 python中assert的用法

assert：断言格式： assert 表达式 [, 参数] 当表达式为真时，程序继续往下执行；当表达式为假时，抛出AssertionError错误，并将参数输出举例： def foo(s): n = int(s) assert n != 0, 'n is zero!' return 10 / n foo('0') # 代码执行结果 # AssertionError: n is zero! 来源： https://www.cnblogs.com/shuaishuaidefeizhu/p/11324654.html

pytest+allure(allure-pytest基于这个插件)生成漂亮的报告+显示

阅读更多关于 pytest+allure(allure-pytest基于这个插件)生成漂亮的报告+显示

一：环境准备 1.python3.6 2.windows环境 3.pycharm 4.allure-pytest 5.allure2.8.0 6.java1.8 allure-pytest快速安装在cmd中输入 pip install allure-pytest，回车二：报告生成第1步：下载allure.zip，下载地址：allure-github: https://github.com/allure-framework/allure2 ，找到对应版本，并下载第2步：解压allure.zip，将路径添加环境变量，path中，记得需要重启电脑第3步：验证allure,在cmd中输入allure,然后回车，如果可以看到一下，说明配置完成第4步：运行测试用例 pytest.main(["-m","login","-s","-q","--alluredir=./report"]) "-m": 标记用例 "login": 被标记需要执行用例 "-s":允许终端在测试运行时输出某些结果，例如你想输入print的内容，可以加上-s "-q"简化输出结果 "--alluredir": 生成allure指定语法 "./report":生成报告的路径 "--clean-alluredir" ：因为这个插件库allure-pytest生成的报告文件，你第二次运行时候不会清理掉里面的东西

Can I use assert on Android devices?

阅读更多关于 Can I use assert on Android devices?

I want to use the Assert keyword in my android apps to destroy my app in some cases on the emulator, or my device during testing. Is this possible? It seems that the emulator just ignores my asserts. JRL The API provides the JUnit Assert . You can do import static junit.framework.Assert.*; now you can use all the functions like assertTrue, assertEquals, assertNull that are provided in the junit framework. Be careful not to import the Junit4 framework through eclipse, that would be the org.junit package. You have to use the junit.framework package to get it working on an android device or the

Dart和JavaScript对比小结

阅读更多关于 Dart和JavaScript对比小结

作为一名web前端来入门dart，新语言和我们熟悉的js有所差异，写dart的过程中容易受到原有思维的影响，这里把dart和js做一个对比总结，方便查找和熟悉。变量声明 var 关键字 dart和js都支持var关键字，使用 var 关键词进行声明的时候，dart 会自动推断出当前变量的类型，如果在变量声明的时候没有进行赋值，那么该类型就是动态的，类似于 TS 的 any。在类型推断上跟 TypeScript 是一致的。众所周知，JavaScript 是一门弱类型的语言，而 Dart 是强类型的语言但dart也支持一些弱类型，Dart 中弱类型有 var , Object 以及 dynamic 大家在学习dart的过程中，可能有疑问：同为弱类型， var , Object 以及 dynamic 有什么区别？ (1) var 初始可定义, 如果有初始值，那么其类型将会被锁定，定义之后不可改变类型 (2) Object 动态任意类型，编译阶段检查类型 (3) dynamic 动态任意类型，编译阶段不检查类型 var 初始化确定类型后不可更改类型， Object 以及 dynamic 可以更改类型 Object 编译阶段检查类型, 而 dynamic 编译阶段不检查类型 // 同样在声明的时候类型 var a = 'defalut'; Object b = 'defalut';

面试官都叫好的Synchronized底层实现，这工资开多少一个月？

阅读更多关于面试官都叫好的Synchronized底层实现，这工资开多少一个月？

本文为死磕Synchronized底层实现第三篇文章，内容为重量级锁实现。本系列文章将对HotSpot的 synchronized 锁实现进行全面分析，内容包括偏向锁、轻量级锁、重量级锁的加锁、解锁、锁升级流程的原理及源码分析，希望给在研究 synchronized 路上的同学一些帮助。重量级的膨胀和加锁流程当出现多个线程同时竞争锁时，会进入到 synchronizer.cpp#slow_enter 方法 void ObjectSynchronizer::slow_enter(Handle obj, BasicLock* lock, TRAPS) { markOop mark = obj->mark(); assert(!mark->has_bias_pattern(), "should not see bias pattern here"); // 如果是无锁状态 if (mark->is_neutral()) { lock->set_displaced_header(mark); if (mark == (markOop) Atomic::cmpxchg_ptr(lock, obj()->mark_addr(), mark)) { TEVENT (slow_enter: release stacklock) ; return ; } // Fall through to

JS的面向对象与原型

阅读更多关于 JS的面向对象与原型

订阅 assert