assert

I am using VC++. Is assert(false) ignored in release mode? activout.se If compiling in release mode includes defining NDEBUG, then yes. See assert (CRT) IIRC, assert(x) is a macro that evaluates to nothing when NDEBUG is defined, which is the standard for Release builds in Visual Studio. The assert macro (at least it is typically a macro) is usually defined to no-op in release code. It will only trigger in debug code. Having said that. I have worked at places which defined their own assert macro, and it triggered in both debug and release mode. I was taught to use asserts for condition which

I am wanting to test a function on one of my models that throws specific errors. The function looks something like this: def merge(release_to_delete) raise "Can't merge a release with itself!" if( self.id == release_to_delete.id ) raise "Can only merge releases by the same artist" if( self.artist != release_to_delete.artist ) #actual merge code here end Now I want to do an assert that when I call this function with a parameter that causes each of those exceptions, that the exceptions actually get thrown. I was looking at ActiveSupport documentation, but I wasn't finding anything promising. Any

This is a rather useless assertion error; it does not tell the values of the expression involved (assume constants used are actually variable names): $ python -c "assert 6-(3*2)" [...] AssertionError Is there a better assert implementation in Python that is more fancy? It must not introduce additional overhead over execution (except when assert fails) .. and must turn off if -O flag is used. Edit : I know about assert's second argument as a string. I don't want to write one .. as that is encoded in the expression that is being asserted. DRY (Don't Repeat Yourself). Install your of function as

For assert macros in my iPhone project, I'm looking for a way to programmatically break into the debugger. On Windows (MSVC++), I can use __debugbreak() for this purpose. Invoking this function will stop my program, launch the debugger, and display a callstack of the line that called __debugbreak(). Is there anything similar to __debugbreak() for the iPhone? I've tried Debugger(), but that gives me a linker error. Thanks, Claus nielsbot edit Turns out this also works: #define Debugger() { raise( SIGINT ) ; } I think it's the same principle. I use this: #define Debugger() { kill( getpid(),

1.目录结构 调用fixture有两种写法： 1.装饰器 @pytest.mark.usefixtures("start") ； 2.直接在用例里面调用fixture装饰的方法当作参数输入def test_demo(self,start)；3.设置fixture参数autouse=True 2.用例传fixture参数 1.项目跟目录下面的全局conftest.py 1 import pytest 2 @pytest.fixture() 3 def start(): 4 print("\n全局conftest") 2.test_case_demo/conftest.py 和 test_demo.py conftest.py 代码1 import pytest 2 @pytest.fixture() 3 def start_1(): 4 print("\n局部test_case_demo") test_demo.py 代码1 import pytest 2 class Test_demo(): 3 def test_demo(self,start,start_1): #标记代码 4 assert 1==1 5 6 if __name__ == '__main__': 7 pytest.main(["-s","-v","test_demo.py"]) 运行结果： 3.test_case

出错处理 文章目录 出错处理 1 出错处理选项 2 C语言机制 2.1 assert宏 2.2 使用预编译 2.3 标准库函数 3 使用系统日志 3.1 openlog函数 3.2 syslog函数 1 出错处理选项 代码段对出错处理有几种选择： 不做处理，这种方法不可取。 检测错误并向用户提供有关信息。 最好的一种出错处理选择是由Linux编程环境通过系统日志记录错误信息，这样可以永久地记录错误信息。 2 C语言机制 2.1 assert宏 宏assert的作用是如果它测试的条件返回错误（0），则终止程序执行。它先计算表达式expression，若其值为假，则先向stderr打印出错信息，然后调用函数abort来终止程序运行。 # include <assert.h> void assert ( int expression ) ; 2.2 使用预编译 2.3 标准库函数 # include <stdlib.h> void abort ( void ) ; void exit ( int status ) ; void atexit ( void ( * fun ) ( void ) ) ; # include <stdio.h> void perror ( const char * s ) ; # include <string.h> char * strerror ( int