area

Check if a latitude and longitude is within a circle

北慕城南 提交于 2019-11-27 17:54:15
See this illustration: What I would like to know is: How to create an area (circle) when given a latitude and longitude and the distance (10 kilometers) How to check (calculate) if a latitude and longitude is either inside or outside the area I would prefer if you can give me code example in Java or specifically for Android with Google Maps API V2 flx What you basically need, is the distance between two points on the map: float[] results = new float[1]; Location.distanceBetween(centerLatitude, centerLongitude, testLatitude, testLongitude, results); float distanceInMeters = results[0]; boolean

Calculating the area under a curve given a set of coordinates, without knowing the function

孤者浪人 提交于 2019-11-27 17:36:51
I have one list of 100 numbers as height for Y axis, and as length for X axis: 1 to 100 with a constant step of 5. I need to calculate the Area that it is included by the curve of the (x,y) points, and the X axis, using rectangles and Scipy. Do I have to find the function of this curve? or not? ... almost all the examples I have read are about a specific equation for the Y axis. In my case there is no equation, just data from a list. The classic solution is to add or the Y points and multiple by the step X distance... using Scipy any idea? Please, can anyone recommend any book which focusing

GPS area in Android

烈酒焚心 提交于 2019-11-27 17:03:36
问题 Is there any class for GPS area calculate? 回答1: I use this code to calculate an area delimited by GPS points with Android: private static final double EARTH_RADIUS = 6371000;// meters public static double calculateAreaOfGPSPolygonOnEarthInSquareMeters(final List<Location> locations) { return calculateAreaOfGPSPolygonOnSphereInSquareMeters(locations, EARTH_RADIUS); } private static double calculateAreaOfGPSPolygonOnSphereInSquareMeters(final List<Location> locations, final double radius) { if

Finding the overlapping area of two rectangles (in C#)

这一生的挚爱 提交于 2019-11-27 16:10:56
问题 Edit: Simple code I used to solve the problem in case anyone is interested (thanks to Fredrik): int windowOverlap(Rectangle rect1, Rectangle rect2) { if (rect1.IntersectsWith(rect2)) { Rectangle overlap = Rectangle.Intersect(rect1, rect2); if (overlap.IsEmpty) return overlap.Width * overlap.Height; } return 0; } Original Question: I'd like to know a quick and dirty way to check if two rectangles overlap and if they do calculate the area of the overlap. For curiosities sake I'm interested in

JFreeChart select an area without zooming

早过忘川 提交于 2019-11-27 15:12:24
问题 I recently started using JFreeChart and there is something i would like to do but i'm not sure if it's possible. My program is supposed to draw a spectrogram (a sound graph) from a wav file. So i managed to get the data from my wav file in a double arraylist and to display it in a chart. But now i would like to be able to select an area of my spectrogram (with the same tool used for zooming) without zooming and to be able to play only the selected part on my sound. But i simply can't find any

MKCoordinateRegionMakeWithDistance equivalent in Android

谁都会走 提交于 2019-11-27 14:04:29
问题 We can set the surrounding area for particular location on map in iPhone as following CLLocationCoordinate2D coord = {latitude:37.09024, longitude:-95.712891}; CLLocationDistance latitudinalMeters; latitudinalMeters =NoOfMiles * 1609.344; CLLocationDistance longitudinalMeters; longitudinalMeters = NoOfMiles * 1609.344; mapViewHome.region = MKCoordinateRegionMakeWithDistance(coord, latitudinalMeters, longitudinalMeters); Is there any equivalent method for Android? 回答1: This code is not

Area of intersection between circle and rectangle

北城余情 提交于 2019-11-27 12:11:39
问题 I'm looking for a fast way to determine the area of intersection between a rectangle and a circle (I need to do millions of these calculations). A specific property is that in all cases the circle and rectangle always have 2 points of intersection. 回答1: Given 2 points of intersection: 0 vertices is inside the circle: The area of a circular segment XXXXX ------------------- X X X X Circular segment X X XX XX +-X-------X--+ XXXXXXXX | X X | | XXXXX | 1 vertex is inside the circle: The sum of

Compute the area of intersection between a circle and a triangle?

风格不统一 提交于 2019-11-27 11:43:10
How does one compute the area of intersection between a triangle (specified as three (X,Y) pairs) and a circle (X,Y,R)? I've done some searching to no avail. This is for work, not school. :) It would look something like this in C#: struct { PointF vert[3]; } Triangle; struct { PointF center; float radius; } Circle; // returns the area of intersection, e.g.: // if the circle contains the triangle, return area of triangle // if the triangle contains the circle, return area of circle // if partial intersection, figure that out // if no intersection, return 0 double AreaOfIntersection(Triangle t,

Select an area to capture using the mouse

我怕爱的太早我们不能终老 提交于 2019-11-27 07:55:13
I'm making a Java based screen shot application, and I want to make it so when you push a combination of keys on your keyboard something like this video happens where you select and area on your screen, and it takes a screen shot of the selected area. How to select an area to capture using the mouse? Start with something like this. import java.awt.*; import java.awt.event.*; import java.awt.image.*; import javax.swing.*; /** Getting a Rectangle of interest on the screen. Requires the MotivatedEndUser API - sold separately. */ public class ScreenCaptureRectangle { Rectangle captureRect;

Combined area of overlapping circles

会有一股神秘感。 提交于 2019-11-27 05:53:33
I recently came across a problem where I had four circles (midpoints and radius) and had to calculate the area of the union of these circles. Example image: For two circles it's quite easy, I can just calculate the fraction of the each circles area that is not within the triangles and then calculate the area of the triangles. But is there a clever algorithm I can use when there is more than two circles? Ants Aasma Find all circle intersections on the outer perimeter (e.g. B,D,F,H on the following diagram). Connect them together with the centres of the corresponding circles to form a polygon.