area

Python: find area of polygon from xyz coordinates

由 左心房为你撑大大i 提交于 2019-11-29 02:52:18
问题 I'm trying to use the shapely.geometry.Polygon module to find the area of polygons but it performs all calculations on the xy plane. This is fine for some of my polygons but others have a z dimension too so it's not quite doing what I'd like. Is there a package which will either give me the area of a planar polygon from xyz coordinates, or alternatively a package or algorithm to rotate the polygon to the xy plane so that i can use shapely.geometry.Polygon().area ? The polygons are represented

GPS area in Android

由 心不动则不痛 提交于 2019-11-29 02:46:00
Is there any class for GPS area calculate? I use this code to calculate an area delimited by GPS points with Android: private static final double EARTH_RADIUS = 6371000;// meters public static double calculateAreaOfGPSPolygonOnEarthInSquareMeters(final List<Location> locations) { return calculateAreaOfGPSPolygonOnSphereInSquareMeters(locations, EARTH_RADIUS); } private static double calculateAreaOfGPSPolygonOnSphereInSquareMeters(final List<Location> locations, final double radius) { if (locations.size() < 3) { return 0; } final double diameter = radius * 2; final double circumference =

Calculating Area of Irregular Polygon in C#

由 感情迁移 提交于 2019-11-28 21:37:52
I've managed to write a 'for dummies' how to calculate the area of irregular polygon in C#, but I need it to be dynamic for any amount of verticies . Can someone please help? Class: public class Vertex { private int _vertexIdx; private double _coordX; private double _coordY; private double _coordZ; public Vertex() { } public Vertex(int vertexIdx, double coordX, double coordY, double coordZ) { _vertexIdx = vertexIdx; _coordX = coordX; _coordY = coordY; _coordZ = coordZ; } public int VertexIdx { get { return _vertexIdx; } set { _vertexIdx = value; } } public double X { get { return _coordX; }

Programmatically take a screenshot of specific area

由 佐手、 提交于 2019-11-28 21:21:45
问题 Like you can see in my code, I take a screenshot and save it to the photo album. //for retina displays if ([[UIScreen mainScreen] respondsToSelector:@selector(scale)]) { UIGraphicsBeginImageContextWithOptions(self.view.bounds.size, NO, [UIScreen mainScreen].scale); } else { UIGraphicsBeginImageContext(self.view.bounds.size); } [self.view.layer renderInContext:UIGraphicsGetCurrentContext()]; UIImage *viewImage = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext();

Find the area between two curves plotted in matplotlib (fill_between area)

由 泪湿孤枕 提交于 2019-11-28 20:35:19
问题 I have a list of x and y values for two curves, both having weird shapes, and I don't have a function for any of them. I need to do two things: (1) plot it and shade the area between the curves like the image below; (2) find the total area of this shaded region between the curves. I'm able to plot and shade the area between those curves with fill_between and fill_betweenx in matplotlib, but I have no idea on how to calculate the exact area between them, specially because I don't have a

Highlight parts of matlab plot

由 十年热恋 提交于 2019-11-28 10:11:21
I have a matlab plot that looks like this: Where the Y values for each of the subplots are stored in single dimensional arrays. What i would like to do is to find an area where the top graph is above a certain height say 0.5. I would also like to highlight the same area in the other graphs as well. Here is an example of what I am talking about: The best i have been able to find so far is the function area which will fill an area on the matlab grid. However, if someone could tell me how to make it transparent and also how to fill multiple areas without having to do lots of area commands that

Cursor not changing to pointer in Usemap/area case

由 梦想与她 提交于 2019-11-28 09:01:45
I have the following HTML code which I cannot get to work quite right in all browsers: <div id ="right_header"> <img id = "usemapsignin" src="/images/sign-in-panel-wo-FB.png" usemap = "#signin"> </div> <map name = "signin" > <area shape = "rect" coords = "30,10, 150, 50" target = "_blank" alt = "signin" id="signin" onMouseOver="document.images['usemapsignin'].style.cursor='pointer'" onMouseOut="document.images['usemapsignin'].style.cursor='auto'"/> <area shape = "rect" coords = "0,113, 172, 150" target = "_blank" alt = "restowner" id = "restowner" onclick = "alert('Hello Restaurant Owner!')" /

Rounding Inaccuracies When Combining Areas in Java?

由 假如想象 提交于 2019-11-28 08:52:51
问题 I'm working with Areas in Java. My test program draws three random triangles and combines them to form one or more polygons. After the Areas are .add() ed together, I use PathIterator to trace the edges. Sometimes, however, the Area objects will not combine as they should... and as you can see in the last image I posted, extra edges will be drawn. I think the problem is caused by rounding inaccuracies in Java's Area class (when I debug the test program, the Area shows the gaps before the

Set a background color on the HTML <area> element?

由 淺唱寂寞╮ 提交于 2019-11-28 07:02:02
问题 Is there any way to set a background color for the HTML <area> element? I'm creating an image map where certain sections of the map will pop up a tooltip when you mouse over them, and I thought it would be cool (and convenient) if I could set a background color for the <area> elements so you could see where they were located over the image. I've tried both background-color and border, and neither have any effect - the <area> elements remain "invisible." I'm assuming this is because <area> is

R Venn Diagram package Venerable unavailable - alternative package?

由 半城伤御伤魂 提交于 2019-11-28 06:47:50
问题 I need to plot area proportional Venn Diagrams with at least 5 variables. I tried to install Vennerable package but its just not available anymore. Link to windows build doesn't work (page not found). Is there an alternative package? 回答1: The source files, last updated in 2007, are downloadable from Sourceforge as a tar.gz file: http://sourceforge.net/projects/vennerable/files/R%20Source%20package/1.1.1.1/Vennerable_1.1.1.1.tar.gz/download Better yet, what appears to be more updated ( Edit:
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