any

I am trying to search in a 2D numpy array for a specific value, the get_above method returns a list of coordinates above the character 'initial char' def get_above(current, wordsearch): list_of_current_coords = get_coords_current(current, wordsearch) #print(list_of_current_coords) length = len(list_of_current_coords) first_coords = [] second_coords = [] for x in range(length): second = list_of_current_coords[x][1] new_first = list_of_current_coords[x][0] - 1 first_coords.append(new_first) second_coords.append(second) combined = [first_coords, second_coords] above_coords = [] for y in range

I have a dataframe that looks like: a A a B a C a D a E a F p A p B p C p D p E p F 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 2 0 1 0 0 0 0 0 0 1 0 0 0 3 0 0 1 0 0 1 0 0 0 0 0 0 4 0 0 0 1 0 1 0 0 0 0 0 0 5 0 0 0 0 1 0 0 0 0 0 0 0 6 0 0 0 0 0 0 1 0 0 0 0 0 df = pd.DataFrame({'p A':[0,0,0,0,0,0,1],'p B':[0,0,0,0,0,0,0],'p C':[0,0,1,0,0,0,0],'p D':[0,0,0,0,0,0,0],'p E':[0,0,0,0,0,0,0],'p F':[0,0,0,0,0,0,0],'a A':[0,1,0,0,0,0,0],'a B':[0,0,1,0,0,0,0],'a C':[0,0,0,1,0,0,0],'a D':[0,0,0,0,1,0,0],'a E':[0,0,0,0,0,1,0],'a F': [0,0,0,1,1,0,0]}) Note: This is a much simplified version of my

I am doind a free Stanford online course (which is pretty cool, you should check that out) and I've been racking my brains for the lest 2 days and can't find an answer to the following problem. Please help. Question 4 Find names and grades of students who only have friends in the same grade. Return the result sorted by grade, then by name within each grade. When I finally thought that I had the answer my query returned all the values from the table Friend. This is the best I could come up with. select h1.id, h1.name, h1.grade, h2.id, h2.name, h2.grade from friend f1 join highschooler h1 on f1

I am comparing the performance of the any() built-in function with the actual implementation the docs suggest: I am looking for an element greater than 0 in the following list: lst = [0 for _ in range(1000000)] + [1] This is the supposedly equivalent function: def gt_0(lst): for elm in lst: if elm > 0: return True return False And these are the results of the performance tests: >> %timeit any(elm > 0 for elm in lst) >> 10 loops, best of 3: 35.9 ms per loop >> %timeit gt_0(lst) >> 100 loops, best of 3: 16 ms per loop I would expect both of the to have the exact same performance, however any()

I have a class object: groupNameData: GroupNameData = new GroupNameData(); and I have an any object groupNameDatas: any; Assignment 1 (class = any) I just assigned the class object values to any object, like this.groupNameDatas = this.groupNameData; It means, this.groupNameDatas (Any) can accept any kind of data, because it's an any object. Assignment 2 (any = class) Now I have reversed the assignment, like this.groupNameData = this.groupNameDatas;// any to class It's also working like my first assignment example. Why it did not throw an error like cannot convert implicitly "any" to

I have a DataFrame and I would like to check if any of the values (v) of a column satisfies x<=v<=y . equal = any(df['columnX'] == value) # No problems here in_between = any(x <= df['columnX'] <= y) # ValueError :/ The error I get is ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all(). But I am using any() already! So what's the problem here? Why does it work with == but not with x<=v<=y ? Use between to do this, it also supports whether the range values are included or not via inclusive arg: In [130]: s = pd.Series(np.random.randn(5)) s