anonymous-function

Say I want to create an anonymous function from a m-file-function that returns two outputs. Is it possible to set up the anonymous function such that it only returns the second output from the m-file-function? Example: ttest2 returns two outputs, t/f and a probability. If I want to use the t-test with cellfun , I might only be interested in collecting the probabilities, i.e. I'd like to write something like this probabilities = cellfun(@(u,v)ttest2(u,v)%take only second output%,cellArray1,cellArray2) There's no way I know of within the expression of the anonymous function to have it select

This question already has an answer here: Official information on `arguments` in ES6 Arrow functions? 2 answers function foo(x) { console.log(arguments) } //foo(1) prints [1] but var bar = x => console.log(arguments) gives the following error when invoked in the same way: Uncaught ReferenceError: arguments is not defined Sylwester Arrow functions don't have this since the arguments array-like object was a workaround to begin with, which ES6 has solved with a rest parameter: var bar = (...arguments) => console.log(arguments); arguments is by no means reserved here but just chosen. You can call

This question already has an answer here: What does the exclamation mark do before the function? 10 answers I was reading JS sources from Twitter — on my way to improve my JS knowledge base, when I came across the strange way of calling anonymous function: !function( $ ) { ... }( window.jQuery ); ... and this works! :) It's obvious to everyone, that this: function ( $ ) { ... } ( window.jQuery ) does not work (Syntax error), while this one is correct: (function ( $ ) { .... })( window.jQuery ) Can anyone please explain this magic (why case with !function works)? When the keyword function is