amazon

问题 Shouldn't we be able to use Universal Links into Amazon on iOS? They are hosting this file: https://www.amazon.com/apple-app-site-association and this blog post seem to be certain of it. However, if I make a link that follows one of their site-association rules, such as http://www.amazon.com/gp/product/0062273205, I keep getting directed to Safari instead of the app. I have never clicked Back to X from the Amazon app, so it can't be that cache that is messing with me. 回答1: Universal Links do

问题 I get the record using primarykey id in amazon dynamodb using java. AccountController.java package com.dynamodb.controller; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestBody; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; import org.springframework.web.bind.annotation.ResponseBody; import com

问题 We're currently using amazon-a2s-2007-10-29-java-library.jar to interact with the Amazon Webservices or Product Advertising API, respectively. We don't see a way how to implement signed requests (mandatory from Aug 15) using this library, nor can we find an updated version supporting signed requests. There does not seem to be too much discussion about this topic around, thus I suspect we're either the only ones using this lib, or otherwise just too blind to see an obvious solution for the

问题 I'm using xpath to scrape a amazon webpage particular, but it doesn't work. Can any one give me some advice? Here's the link to that page: a link I want to scrape these: "Fun, credit card-sized prints" The code i'm using is here: from lxml import html import requests url = 'http://www.amazon.co.uk/dp/B009CX5VN2' page = requests.get(url) tree = html.fromstring(page.text) feature_bullets = tree.xpath('//*[@id="feature-bullets"]/ul/li[1]/span/text()') But the feature_bullets is always empty.

问题 Hey is it possible to change the external IP address of my Amazon EC2 instance without restarting the thing? Any help would be appreciated, the reason why I want to do this is because restarting will charge me for the full hour. 回答1: Yes, you can associate/disassociate an Elastic IP without restarting the EC2 instance. It can be done from the "Elatic IPs" screen of the AWS Management Console, EC2 section. 来源： https://stackoverflow.com/questions/18806354/change-ec2-external-ip-without

问题 Relating to (or following on from) the question: How does AWS transfer S3 objects to Glacier archives when you use lifecycle archive rules? - where it is explained that S3 is essentially just another multi-tennanted 'customer' of Glacier - does that mean I'm completely unable to configure notification events on the 'default' Glacier vault? In S3, I'm unable to specify a vault to archive to, so are Glacier notifications only of purpose for bespoke apps that use the API's to handle their

问题 I have an android app, which is using IAP. I'm sending PurchasingManager.initiateGetUserIdRequest() and getting the user ID successfully in onGetUserIdResponse . After getting the response the PurchasingManager.initiatePurchaseRequest("sku") is invoked, but unfortunately the desired onPurchaseResponse seems never be called. My applications IAP items are approved by amazon. Any help on this? 回答1: In our case, the issue ended up being that we had added the android:exported="false" flag to our

问题 I want to upload an image to an amazon s3 bucket in android. I don't get any errors but it's just not working can anybody help me? I can't find any good examples or questions about this. I assign a image to 'File images3' images3 = new File(uri.getPath()); public void addEventToDB(){ Thread thread = new Thread() { @Override public void run() { try { CognitoCachingCredentialsProvider credentialsProvider = new CognitoCachingCredentialsProvider( getActivity().getApplicationContext(), // get the

问题 There are many similar Stackoverflow questions. All have answers that suggest using methods like getInstallerPackageName on the PackageManager class. All also have comments or conflicting answers saying that this is not a reliable approach, suggesting that the only way to reliably check which store installed a given App is to generate two separate binaries, each with a storeFlag set, and upload one binary to Amazon and one to Google Play. I need to know which store is the App's installer so

问题 I am trying to create a simple Alexa skill using Flask Ask in python. I have an intent called "SearchIntent" with a "searchterm" slot and the python code looks something like this: @ask.intent("SearchIntent") def SearchIntent(searchterm): resList = [] searchterm = searchterm.lower() for item in somelist: if item.find(searchterm) != -1: resList.append(item) return question("I Found " + str(len(resList)) + ", Do you want me to list them all?") I want to check if the response from the user, if