ajaxform

jquery表单验证插件 jquery.form.js

社会主义新天地 提交于 2019-12-04 05:56:49
Form插件,支持Ajax,支持Ajax文件上传,功能强大,基本满足日常应用。 1.JQuery框架软件包下载 http://docs.jquery.com/Downloading_jQuery 2. Form插件下载 https://github.com/malsup/form/blob/master/jquery.form.js 3、Form插件的简单入门 第一步:先增加一个表单 <form id="myForm" action="comment.php" method="post"> Name: <input type="text" name="name" /> Comment: <textarea name="comment"></textarea> <input type="submit" value="Submit Comment" /> </form> 第二步:jquery.js和form.js文件的包含 <head> <script type="text/javascript" src="path/to/jquery.js"></script> <script type="text/javascript" src="path/to/form.js"></script> <script type="text/javascript"> // wait for the

How to use ajax link instead of submit button for form?

守給你的承諾、 提交于 2019-12-04 02:29:58
问题 I have Ajax Form in my view: @using (Ajax.BeginForm("SearchHuman", "Search", new AjaxOptions(){ InsertionMode = InsertionMode.Replace, UpdateTargetId = "result" })) { <div class="editor-field"> @DescriptionStrings.Lastname: @Html.TextBox("LastName") </div> <div class="editor-field"> @DescriptionStrings.Firstname: @Html.TextBox("Name") </div> //submit button <input type="submit" value='Start Searching' /> //submit link @Ajax.ActionLink("search", "OtherSearch", new{lastName ="",...}, new

strange behavior using $('.ajax_form').ajaxForm();

走远了吗. 提交于 2019-12-03 17:32:37
It is my first time to apply jquery ajaxForm on a class like the following <form class="ajax_form"...><input type="text" name="q" /><input type="submit" /></form> <form class="ajax_form"...><input type="text" name="q" /><input type="submit" /></form> <script> $('.ajax_form').ajaxForm({ dataType: 'json', error: ajaxErrorHandler, success: function(response) { // do some ui update .. } }); </script> Now after Ajax call is completed I always get into error section although firebug didn't report any errors response not sure what I did wrong. This may or not be appropriate in this case, but I'll

how to perform some action before submit form via .ajaxForm()?

寵の児 提交于 2019-12-03 12:50:53
i am using ajaxForm() frame work to send my data without reloading my page. $('#ReplayForm').ajaxForm({ success : function(data){ alert("Success"); } }); now, i want to check some condition before submitting the form and if the condition is false then stop submission else continue. is there any solution to do this work or is there any way buy which i can perform this operation. Thanks in advance. Ashish Vaghasiya Yes, definatly you can handle this situation. you have to call beforesubmit method for this let see one example $('#ReplayForm').ajaxForm({ beforeSubmit : function(arr, $form, options

move_uploaded_file() Unable to move file from tmp to dir

做~自己de王妃 提交于 2019-12-03 07:20:37
I've been searching for the solution but I can't find the answer. I created a image upload form. It runs with ajaxform plugin. But still it doesn't upload to the directory. The error_log says move_uploaded_file() Unable to move file from [tmp] to [dir]. Then on the front end it says Upload Complete. But when the file is called, it doesn't exist. HTML CODE: <div class="imgupload hidden"> <form id="profpicform" action="" method="post" enctype="multipart/form-data"> <input type="file" size="60" name="profpic"> <input type="submit" value="Submit File"> </form> <div class="imguploadStatus"> <div

jquery.form.js官方插件介绍Form插件,支持Ajax,支持Ajax文件上传

别来无恙 提交于 2019-12-03 03:02:21
[JQuery框架应用]:form.js官方插件介绍 Form插件,支持Ajax,支持Ajax文件上传,功能强大,基本满足日常应用。 1、JQuery框架软件包下载 文件: jquery.rar 大小: 29KB 下载: 下载 2、Form插件下载 文件: jquery.form.rar 大小: 7KB 下载: 下载 3、Form插件的简单入门 第一步:先增加一个表单 < form id = "myForm" action = "comment.php" method = "post" > Name : < input type = "text" name = "name" / > Comment : < textarea name = "comment" > < / textarea > < input type = "submit" value = "Submit Comment" / > < / form > 第二步:jquery.js和form.js文件的包含 < head > < script type = "text/javascript" src = "path/to/jquery.js" > < / script > < script type = "text/javascript" src = "path/to/form.js" > < / script > <

CakePHP ajax CSRF token mismatch

匿名 (未验证) 提交于 2019-12-03 01:05:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am making an ajax request with Csrf component load in my AppController However I get the error {"message":"CSRF token mismatch.","url":"\/module_slides\/loadDeck.json","code":403} Here is the request header POST /module_slides/loadDeck.json HTTP/1.1 Host: www.hotelieracademy.com Connection: keep-alive Content-Length: 18 Origin: https://www.hotelieracademy.com X-XSRF-TOKEN: 3d3901b1de9c5182dce2877c9e1d9db36cdf46a6 User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/46.0.2490.86 Safari

Malsup's jQuery form plugin and JSF 2.2

一世执手 提交于 2019-12-02 12:30:12
Is it possible to use Malsup's plugin to upload files like this example using JSF 2.2 so I can use its progress bar? On html forms, it seems to work around the 'name' attribute from the <input type="file"> s, all 3 being "myfile[]" in the example. Unfortunately, its equivalent in jsf is <h:inputFile> , which doesn't have a name attribute. Well, <h:inputFile> can have an id and then its name will have the same value in the generated html, but since ids are unique, so will be their names. The thing is, I don't know how/if the names impact on how the plugin handles a submit with multiple inputs.

How to make AjaxForm work with several forms loaded using jquery load()?

折月煮酒 提交于 2019-12-02 04:39:56
问题 I have a page with a div that is dynamically filled using a paginator ;-) At page init I load the first 10 forms in it using jquery .load() method. What I'd like to do is to make all the forms dynamically updatable using AjaxForm plugin. I know about server side, let's call it update.asp. It works. But there are several questions: How to make plugin work in the first place as the AjaxForm seems not to work to the firms inside a dynamically loaded div? How do I ID and name the forms? Now I

How to make AjaxForm work with several forms loaded using jquery load()?

房东的猫 提交于 2019-12-02 01:06:14
I have a page with a div that is dynamically filled using a paginator ;-) At page init I load the first 10 forms in it using jquery .load() method. What I'd like to do is to make all the forms dynamically updatable using AjaxForm plugin. I know about server side, let's call it update.asp. It works. But there are several questions: How to make plugin work in the first place as the AjaxForm seems not to work to the firms inside a dynamically loaded div? How do I ID and name the forms? Now I used ID and name myForm to all of them (maybe that is why it doesn't work). Because if I use name myForm1,