aggregate

Aggregating hourly data into daily aggregates with missing value in R

╄→尐↘猪︶ㄣ 提交于 2020-01-07 07:47:09
问题 [enter image description here][1][enter image description here][2]I have a data frame "RH", with hourly data and I want to convert it to daily maximum and minimum data. This code was very useful [question]:Aggregating hourly data into daily aggregates RH$Date <- strptime(RH$Date,format="%y/%m/%d) RH$day <- trunc(RH$Date,"day") require(plyr) x <- ddply(RH,.(Date), summarize, aveRH=mean(RH), maxRH=max(RH), minRH=min(RH) ) But my first 5 years data are 3 hours data not hourly. so no results for

R: aggregate by date - (every 30min mean) [closed]

核能气质少年 提交于 2020-01-07 02:52:09
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . I have been struggling with this for a while now: I have a data frame that contains 5-minute measurements (for around 6 months) of different parameters. I want to aggregate them and get the mean of every parameter every 30 min. Here is a short example: TIMESTAMP <- c("2015-12-31 0:30", "2015-12-31 0:35","2015-12

Aggregate hourly means based on compound field expression

扶醉桌前 提交于 2020-01-06 16:30:15
问题 I am trying to calculate the hourly mean of x in a data frame similar to this: min hour day month year x 1 10 22 31 12 2013 18.3 2 30 22 31 12 2013 16.5 3 50 22 31 12 2013 15.7 4 10 23 31 12 2013 16.7 5 30 23 31 12 2013 18.0 6 50 23 31 12 2013 18.1 7 10 0 1 1 2014 17.4 8 30 0 1 1 2014 15.4 9 50 0 1 1 2014 16.9 I have tried different things with the aggregate function but without luck. So what I want is to calculate the mean of x if the value of hour , day , month , year are the same. The

“column XYZ must be in group by” --> “cannot group by aggregate column”

谁说胖子不能爱 提交于 2020-01-06 15:17:36
问题 i have trouble with following sql-statement (trimmed): SELECT nr, (CASE WHEN SUM(vkdtab.amount*liter)<>0 AND jjjjmm BETWEEN 201001 and 201009 THEN SUM(net)/SUM(vkdtab.amount*liter) ELSE 0 END) as return FROM tab GROUP BY 1,2,3 It should give me the amount/liter of items in a special timeframe, but I get the error: column return must be in group by After I add that column: cannot group by aggregate column . This is functional, just without the timeframe: CASE WHEN SUM(vkdtab.amount*liter)<>0

wso2 esb: Construct one message from multiple web service calls

醉酒当歌 提交于 2020-01-06 13:26:27
问题 I have a number of web services each returning a list of user ids as follows: <application name="abc"> <users> <id>123</id> <id>456</id> <id>789</id> </users> </application> I need to be able to Call a proxy service with a specific id (for example 123); Call each webservice and search for the ID; Create a response for each webservice and finally Aggregate all responses in one message which is sent to the client as follows: <response> <id>123</id> <application name="abc"> found </application>

Grouping + aggregation of itab with table comprehensions

穿精又带淫゛_ 提交于 2020-01-06 08:15:12
问题 Rather typical task but I'm stuck on doing it in a beautiful way. For example, I need to find the last shipment for each vendor, i.e. to find delivery with the max date for the each vendor VENDOR DELIVERY DATE 10 00055 01/01/2019 20 00070 01/19/2019 20 00088 01/20/2019 20 00120 11/22/2019 40 00150 04/01/2019 40 00200 04/10/2019 The result table to be populated VENDOR DELIVERY DATE 10 00055 01/01/2019 20 00120 11/22/2019 40 00200 04/10/2019 I implemented this in a following way, via DESCENDING

Grouping + aggregation of itab with table comprehensions

走远了吗. 提交于 2020-01-06 08:14:15
问题 Rather typical task but I'm stuck on doing it in a beautiful way. For example, I need to find the last shipment for each vendor, i.e. to find delivery with the max date for the each vendor VENDOR DELIVERY DATE 10 00055 01/01/2019 20 00070 01/19/2019 20 00088 01/20/2019 20 00120 11/22/2019 40 00150 04/01/2019 40 00200 04/10/2019 The result table to be populated VENDOR DELIVERY DATE 10 00055 01/01/2019 20 00120 11/22/2019 40 00200 04/10/2019 I implemented this in a following way, via DESCENDING

Aggregate table using linq to entities

心不动则不痛 提交于 2020-01-06 06:48:24
问题 I've a table like this Id MachineName ServerName TagName TagValue ValueDateTime 1 DanPac_A Daniel.Device Links.1 Poll.Registers Block 0.STR02_METER_DENSITY_(1) 93.1631400000 2018-06-04 21:08:28.720 2 DanPac_A Daniel.Device Links.1 Diagnostics.Heartbeat 1.0000000000 2018-06-04 21:08:32.717 3 DanPac_A Daniel.Device Links.1 Poll.Registers Block 0.310-TT-302_(6) 52.1062000000 2018-06-04 21:08:32.873 4 DanPac_A Daniel.Device Links.1 Poll.Registers Block 0.310-TT-302_(6) 52.1062000000 2018-06-04 21

Aggregate table using linq to entities

允我心安 提交于 2020-01-06 06:48:18
问题 I've a table like this Id MachineName ServerName TagName TagValue ValueDateTime 1 DanPac_A Daniel.Device Links.1 Poll.Registers Block 0.STR02_METER_DENSITY_(1) 93.1631400000 2018-06-04 21:08:28.720 2 DanPac_A Daniel.Device Links.1 Diagnostics.Heartbeat 1.0000000000 2018-06-04 21:08:32.717 3 DanPac_A Daniel.Device Links.1 Poll.Registers Block 0.310-TT-302_(6) 52.1062000000 2018-06-04 21:08:32.873 4 DanPac_A Daniel.Device Links.1 Poll.Registers Block 0.310-TT-302_(6) 52.1062000000 2018-06-04 21

Handling NA's in aggregate function in R

痞子三分冷 提交于 2020-01-05 16:58:08
问题 I am trying to get the daily sum from a csv file using the aggregate function but I am encountering the following errors: Error in Summary.factor(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), na.rm = FALSE) : ‘sum’ not meaningful for factors Calls: aggregate ... aggregate.data.frame -> lapply -> FUN -> lapply -> Summary.factor Execution halted Here is the link to the data Data Here's my code: dat<-read.csv("Laoag_tc_induced.csv",header=TRUE,sep=",") dat[dat == -999] <- NA dat[dat == -888] <- 0 dat$Date