32bit-64bit

I'm sure most Windows developers are familiar with this error message, usually when trying to mix 32- and 64-bit executables. In particular Python and Java can both get it. %1 is not a valid Win32 application. It's clear that %1 represents the first argument to the failing command - i.e. the executable that is trying to be loaded - but why does it not get filled in with the actual path? Is it something that the caller is doing wrong, or is it a basic failing of some Windows subsystem that cannot be fixed for compatibility reasons? Mark Ransom The error message comes from Windows itself, you

Google is warning developers that starting Aug 1, 2019, all apps must be 64-bit. I use Cordova to build our web app into an Android app and upload the generated 32-bit APK file into google play store The Cordova crosswalk plugin allow me to build both 32-bit and 64-bit versions using the commands cordova build android --release and cordova build android --release --xwalk64bit respectively. I used the same android version code for both the APKs when build Questions: Earlier I used to upload only the 32-bit version into the play store(Production Track). Right now, Since I have both 32-bit and 64

I'm using this code in XP 32-bit OS to get the %windir%\windows\system32 folder path. sysFolderPath = Environment.GetFolderPath(Environment.SpecialFolder.System) What I want to know is that will this same code return the %windir%\windows\syswow64 folder when used in Windows 7 (64/32-bit)? It will return c:\windows\system32, even in a 32-bit program that runs on the 64-bit version of Windows. Do not fix this, it doesn't need fixing. Because when you use that path, Windows will automatically remap it to c:\windows\syswow64. The file system redirector takes care of it. I tried on my Windows7 box

Which operation i.e a 32 bit operation or a 64 bit operation (like masking a 32 bit flag or a 64 bit flag), would be cheaper on a 64 bit machine? As you don;t specify an architecture, I can suggest only a general answer, as it depends on the operation and on the processor architecture in question. Once you have the data in a CPU register, then most operations will usually take the same amount of time regardless of whether the value was originally 32 or 64 bit. However, there can be some differences on some architectures in how the data gets into a register. Here are some situations where a

Few Questions :): How to identify what JVM is currently installed ? (64 bit / 32 bit) Do I need to do some considerations while programming for 64 bit JVM target Platform ? Can my Java code work on 32 bit as well as 64 bit JVM ? How to run my Java App on 64 bit JVM ? How to identify what JVM is being used for my Java App ? Normally a 64 bit jvm will identify itself as such. 32/64 bit Considerations I have seen: address space - if you're not expecting to address more that 1.3Gb of memory then you won't see a difference native libraries - if you're loading any JNI libs, then they will need to

When attempting to run the following assembly program: .globl start start: pushq $0x0 movq $0x1, %rax subq $0x8, %rsp int $0x80 I am receiving the following errors: dyld: no writable segment Trace/BPT trap Any idea what could be causing this? The analogous program in 32 bit assembly runs fine. OSX now requires your executable to have a writable data segment with content, so it can relocate and link your code dynamically. Dunno why, maybe security reasons, maybe due to the new RIP register. If you put a .data segment in there (with some bogus content), you'll avoid the "no writable segment"