Urllib2 runs fine if i run the program independently but throws error when i add it to a cronjob

问题:

 url = "www.someurl.com"  request = urllib2.Request(url,header={"User-agent" : "Mozilla/5.0"})  contentString = urllib2.url(request).read()  contentFile = StringIO.StringIO(contentString)  for i in range(0,2):     html = contentFile.readline()  print html 

The above code runs fine from commandline but if i add it to a cron job it throws the following error:

  File "/usr/lib64/python2.6/urllib2.py", line 409, in _open     '_open', req)   File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain     result = func(*args)   File "/usr/lib64/python2.6/urllib2.py", line 1186, in http_open     return self.do_open(httplib.HTTPConnection, req)   File "/usr/lib64/python2.6/urllib2.py", line 1161, in do_open     raise URLError(err) urllib2.URLError:  

I did look at some tips on the other forums and tried it but it has been of no use.

Any help will be much appreciated.

回答1:

The environment variables that were used by crontab and from the command line were different.

I fixed this by adding */15 * * * * . $HOME/.profile; /path/to/command.

This made the crontab to pick up enivronment variables that were specified for the system.

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