I have a binary file that I have to parse and I'm using Python. Is there a way to take 4 bytes and convert it to a single precision floating point number?
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问题:
回答1:
>>> import struct >>> struct.pack('f', 3.141592654) b'\xdb\x0fI@' >>> struct.unpack('f', b'\xdb\x0fI@') (3.1415927410125732,) >>> struct.pack('4f', 1.0, 2.0, 3.0, 4.0) '\x00\x00\x80?\x00\x00\x00@\x00\x00@@\x00\x00\x80@'
回答2:
You'll want the struct package.