Is sizeof(size_t) == sizeof(void*) always true?

问题:

Does the C99/C++11 standard guarantee that sizeof(size_t) == sizeof(void*) is always true?

size_t f(void* p) {     return (size_t)(p); // Is it safe? }  void* f(size_t n) {     return (void*)(n); // Is it safe? } 

回答1:

No, that is not guaranteed. Use intptr_t or uintptr_t to safely store a pointer in an integer.

There are/were architectures where it makes sense for that to be false, such as the segmented DOS memory model. There the memory was structured in 64k segments - an object could never be larger than a segment, so 16-bit size_t would be enough. However, a pointer had "segment" and "offset" parts, so it would by definition have to be larger than 16 bits to be able to refer to different segments.

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