Using numpy, how can I do the following:
ln(x)
Is it equivalent to:
np.log(x)
I apologise for such a seemingly trivial question, but my understanding of the difference between log
and ln
is that ln
is logspace e?
Using numpy, how can I do the following:
ln(x)
Is it equivalent to:
np.log(x)
I apologise for such a seemingly trivial question, but my understanding of the difference between log
and ln
is that ln
is logspace e?
np.log
is ln
, whereas np.log10
is your standard base 10 log.
Relevant documentation:
http://docs.scipy.org/doc/numpy/reference/generated/numpy.log.html
http://docs.scipy.org/doc/numpy/reference/generated/numpy.log10.html
Correct, np.log(x)
is the Natural Log (base e
log) of x
.
For other bases, remember this law of logs: log-b(x) = log-k(x) / log-k(b)
where log-b
is the log in some arbitrary base b
, and log-k
is the log in base k
, e.g.
here k = e
l = np.log(x) / np.log(100)
and l
is the log-base-100 of x
from numpy.lib.scimath import logn from math import e #using: x - var logn(e, x)