C reverse binary [duplicate]

问题:

Possible Duplicate:
C reverse bits in unsigned integer

How can I reverse a binary number only using binary operators?

E.g:

11100000 -> 00000111 00110100 -> 00101100 00111111 -> 11111100 

回答1:

For this sort of thing I recommend that you take a look at the awesome page Bit Twiddling Hacks.

Here is just one example solution taken from that page:

Reverse the bits in a byte with 3 operations (64-bit multiply and modulus division)

unsigned char b; // reverse this (8-bit) byte  b = (b * 0x0202020202ULL & 0x010884422010ULL) % 1023; 

And as pointed out in the comments, here's another option:

Reverse an N-bit quantity in parallel in 5 * lg(N) operations

unsigned int v; // 32-bit word to reverse bit order  // swap odd and even bits v = ((v >> 1) & 0x55555555) | ((v & 0x55555555) << 1); // swap consecutive pairs v = ((v >> 2) & 0x33333333) | ((v & 0x33333333) << 2); // swap nibbles ...  v = ((v >> 4) & 0x0F0F0F0F) | ((v & 0x0F0F0F0F) << 4); // swap bytes v = ((v >> 8) & 0x00FF00FF) | ((v & 0x00FF00FF) << 8); // swap 2-byte long pairs v = ( v >> 16             ) | ( v               << 16); 

回答2:

Take a look at Bit Twiddling Hacks. There's an entire section on reversing bit sequences.

回答3:

You can see this website http://graphics.stanford.edu/~seander/bithacks.html

Reversing bit sequences
Reverse bits the obvious way
Reverse bits in word by lookup table
Reverse the bits in a byte with 3 operations (64-bit multiply and modulus division)
Reverse the bits in a byte with 4 operations (64-bit multiply, no division)
Reverse the bits in a byte with 7 operations (no 64-bit, only 32)
Reverse an N-bit quantity in parallel with 5 * lg(N) operations

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