My code is following.
import csv import openpyxl import sys def convert(input_path, output_path): """ Read a csv file (with no quoting), and save its contents in an excel file. """ wb = openpyxl.Workbook() ws = wb.worksheets[0] with open(input_path) as f: reader = csv.reader(f, delimiter='\t', quoting=csv.QUOTE_NONE) for row_index, row in enumerate(reader): for col_index, value in enumerate(row): ws.cell(row=row_index, column=col_index).value = value wb.save(output_path) def main(): try: input_path, output_path = sys.argv[1:] except ValueError: print 'Usage: python %s input_path output_path' % (sys.argv[0],) else: convert(input_path, output_path) if __name__ == '__main__': main()
But I got this error.
Traceback (most recent call last): File "txt2xlsx.py", line 33, in <module> main() File "txt2xlsx.py", line 29, in main convert(input_path, output_path) File "txt2xlsx.py", line 18, in convert ws.cell(row=row_index, column=col_index).value = value File "C:\python27\lib\site-packages\openpyxl\worksheet\worksheet.py", line 350, in cell column = get_column_letter(column) File "C:\python27\lib\site-packages\openpyxl\utils\__init__.py", line 100, in get_column_letter raise ValueError("Invalid column index {0}".format(idx)) ValueError: Invalid column index 0
I think I have installed openpyxl correctly.
And I remember I was using this program without any problem before. I recently bought a new computer so maybe this is a PC configuration issue.. But I can't figure out.