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问题:
I need to count unique values in range (C2:C2080) in excel. Googled formula:
=SUM(IF(FREQUENCY(MATCH(C2:C2080;C2:C2080;0);MATCH(C2:C280;C2:C2080;0))>0;1))
return incorrect value.
UPD: Lame solution:
Sub CountUnique() Dim i, count, j As Integer count = 1 For i = 1 To 470 flag = False If count > 1 Then For j = 1 To count If Sheet1.Cells(i, 3).Value = Sheet1.Cells(j, 11).Value Then flag = True End If Next j Else flag = False End If If flag = False Then Sheet1.Cells(count, 11).Value = Sheet1.Cells(i, 3).Value count = count + 1 End If Next i Sheet1.Cells(1, 15).Value = count End Sub
回答1:
=SUM(IF(FREQUENCY(IF(LEN(A2:A10)>0,MATCH(A2:A10,A2:A10,0),""), IF(LEN(A2:A10)>0,MATCH(A2:A10,A2:A10,0),""))>0,1))
http://office.microsoft.com/en-us/excel/HP030561181033.aspx
You may also write a VBA macro (not sure if that's what you're after though.)
Something to the effect of (given a spreadsheet with A1-A11 filled and B1-B11 empty):
Sub CountUnique() Dim count As Integer Dim i, c, j As Integer c = 0 count = 0 For i = 1 To 11 Sheet1.Cells(i, 2).Value = Sheet1.Cells(i, 1).Value c = c + 1 For j = 1 To c If CDbl(Sheet1.Cells(i, 1).Value) = CDbl(Sheet1.Cells(j, 2).Value) Then c = c - 1 Exit For End If Next j Next i ' c now equals the unique item count put in the 12'th row Sheet1.Cells(12, 1).Value = c End Sub
回答2:
Here is a VBA function that works for me.
You can use it as a worksheet function, referencing any range, eg “=CountUnique(N8:O9)”
It handles text and numeric values, and treats blank cells as one value
It does not require dealing with array functions.
It requires a reference to the Microsoft Scripting Library, for the dictionary object.
Public Function CountUnique(rng As Range) As Integer Dim dict As Dictionary Dim cell As Range Set dict = New Dictionary For Each cell In rng.Cells If Not dict.Exists(cell.Value) Then dict.Add cell.Value, 0 End If Next CountUnique = dict.Count End Function
回答3:
Try:
=SUM(IF(FREQUENCY(C2:C2080,C2:C2080)>0,1))
EDIT: The above will handle blank entries in the column
回答4:
JustinG's function works very well (and fast) until the number of unique items exceeds 32,767 due to some type of limit in Excel.
I found if you modify his code
Public Function CountUnique(rng As Range) As Integer
and make it as...
Public Function CountUnique(rng As Range) As Long
It will then handle more unique items.
回答5:
You could also simply use a filter to temporarily display unique values, and count the filtered values.
回答6:
For anyone still trying to use @JustinG's dictionary method, you will need to alter the code slightly if you're using a newer version of VBA.
You'll need to reference 'Microsoft Scripting Runtime' and prefix the Dictionary
terms with Scripting
, as follows:
Public Function CountUnique(rng As Range) As Long Dim dict As Scripting.Dictionary Dim cell As Range Set dict = New Scripting.Dictionary For Each cell In rng.Cells If Not dict.Exists(cell.Value) Then dict.Add cell.Value, 0 End If Next CountUnique = dict.Count End Function
回答7:
The formula works for me. There are a few things that could cause this to not work. First, all target cells must have a value in them. Another example of where this might not work is if you have one cell with the value 31 and another cell with a text value of "31". It will recognize these as different values.
You could try this:
=SUM(IF(FREQUENCY(IF(LEN(B2:B11)>0,MATCH(B2:B11,B2:B11,0),""), IF(LEN(B2:B11)>0,MATCH(B2:B11,B2:B11,0),""))>0,1))
This is an array formula. Instead of hitting just enter to confirm it you must hit ctrl+shift+enter.
Which is from:
http://www.cpearson.com/excel/Duplicates.aspx
回答8:
After reading through this and then investigating further, I've got one that works better for me than anything I see here:
Array-enter:
(Ctrl+Shift+Enter, and don't include the curly brackets)
{=SUM(IFERROR(1/COUNTIF(C2:C2080,C2:C2080),0))}
Or in VBA:
MyResult = MyWorksheetObj.Evaluate("=SUM(IFERROR(1/COUNTIF(C2:C2080,C2:C2080),0))")
It works for both numbers and text, it handles blank cells, it handles errors in referenced cells, and it works in VBA. It's also one of the most compact solutions I've seen. Using it in VBA, it apparently automatically handles the need to be an array formula.
Note, the way it handles errors is by simply including them in the count of uniques. For example, if you have two cells returning #DIV/0! and three cells returning #VALUE!, those 5 cells would add 2 to the final count of unique values. If you want errors completely excluded, it would need to be modified for that.
In my tests, this one from Jacob above only works for numbers, not text, and does not handle errors in referenced cells (returns an error if any of the referenced cells returns an error):
=SUM(IF(FREQUENCY(G4:G29,G4:G29)>0,1))
回答9:
This might be a more efficient way of dealing with a large number of rows. This uses the inbuilt AdvancedFilter command instead of cycling through each cell at a time.
Public Function UniqueValues(oRange As Range) As Variant ' Uses the built-in AdvancedFilter Excel command to return the unique values onto the Worksheet ' and then populate and retuns an array of unique values ' Note: The index:0 element in the returned array will be the header row. ' You can ignore this element unless the first row in your oRange is a unique value ' in which case the header will be that value. Dim oTarget As Range Dim r As Long, numrows As Long Dim vs1, vs2 As Variant ' Get the first unused cell on the first row where the unique vaues will be temporarily populated Set oTarget = oRange.SpecialCells(xlLastCell) ' the last cell on the worksheet Set oTarget = oTarget.Parent.Cells(1, oTarget.Column + 1) ' the first unused cell on the first row ' Copy the unique values from your oRange to the first unused cell on row 1 oRange.AdvancedFilter Action:=xlFilterCopy, CopyToRange:=oTarget, Unique:=True ' Get the number of rows including the first row which is the header numrows = WorksheetFunction.CountA(oTarget.EntireColumn) ' create an 2-dim array of the rows vs1 = oTarget.Resize(numrows) ' Prepare a second 1-dim array for the result ReDim vs2(numrows) ' Transfer the 2-dim array into the 1-dim array For r = 1 To UBound(vs1, 1) vs2(r - 1) = vs1(r, 1) Next ' Return the 1-dim array as the function result UniqueValues = vs2 ' Clean up the extra column on the worksheet oTarget.EntireColumn.Delete End Function
回答10:
Another way to do this is this:
Sub CountUnique() Dim Count, x, a, lastRow, Values(), StringValues a = ActiveCell.Column a = GetLetterFromNumber(a) lastRow = Range(a & Rows.Count).End(xlUp).row Count = 0 For Each c In Range(Range(a & "1"), Range(a & Rows.Count).End(xlUp)) If c.row = 1 Then ReDim Values(lastRow) Values(Count) = c.Value Count = Count + 1 End If StringValues = Join(Values, "#") StringValues = "#" + StringValues If InStr(1, StringValues, c.Value) = 0 Then Values(Count) = c.Value Count = Count + 1 End If Next c MsgBox "There are " & Count & " unique values in column " & a End Sub
You just have to have the active cell be on row 1 of the column that you are counting.