jquery (ajax) redirect to another domain

匿名 (未验证) 提交于 2019-12-03 02:29:01

问题:

I have the jquery json request in the following format:

JSON request:

$.getJSON('http://xyz.com',function(result) {}); 

If the request fails(server not responds), how do i redirect to another domain. for example "http://zxy.com".(we maintaining the same code in another server)

回答1:

Did you try this?

function addImage(item) {  $("<img/>").attr("src", item.media.m).appendTo("#images"); }      var jqxhr = $.getJSON("http://xyz.com",function(data) {     $.each(data.items, function(i,item){  //sample        addImage(item);     })     .error(function() {                var jqxhrFailover = $.getJSON("http://zzz.com", function(data) {     $.each(data.items, function(i,item){  //sample        addImage(item);     }).error(function(){ alert('both failed!'); }); 


回答2:

I think that it may be better to use $.ajax(), error method or success if the server tells you based on the response).

Then use this to redirect the browser.

window.location = "http://www.google.com" 


回答3:

$.getJSON() is defined as:

jQuery.getJSON=function(url,data,callback){     return jQuery.get(url,data,callback,"json"); }; 

and as such, fails silently.

To react to errors you'll need to use the $.ajax() function directly which allows you to define an onError handler, as in:

$.ajax({     url: '...',      contentType:'json',      success:function(result,stat,xhr){         ...     },      error:function(xhr,opts,err){         ...     } }); 

See jQuery Ajax error handling, show custom exception messages for further information.



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