问题:

I'm not sure why, but for some reason, whenever I have "region" in the file name of the output file, it gives me this error:

IOError: [Errno 22] invalid mode ('w') or filename: 'path\regionlog.txt'

It does this for "region.txt", "logregion.txt", etc.

class writeTo:     def __init__(self, stdout, name):        self.stdout = stdout        self.log = file(name, 'w') #here is where it says the error occurs  output = os.path.abspath('path\regionlog.txt') writer = writeTo(sys.stdout, output) #and here too

Why is this? I really would like to name my file "regionlog.txt" but it keeps coming up with that error. Is there a way around it?

回答1:

Use forward slashes:

'path/regionlog.txt'

Or raw strings:

r'path\regionlog.txt'

Or at least escape your backslashes:

'path\\regionlog.txt'

\r is a carriage return.

Another option: use os.path.join and you won't have to worry about slashes at all:

output = os.path.abspath(os.path.join('path', 'regionlog.txt'))

回答2:

In C standard language, \t, \n, \r are escape characters. \t is a transverse to the next TAB position. \n is a newline and \r is a carriage return. You should use \\r or /r, and you will solve the problem!

回答3:

Additionaly, Python also gives this message when trying to open a file > 50 MB from a SharePoint shared drive.

https://support.microsoft.com/en-us/help/2668751/you-cannot-download-more-than-50-mb-or-upload-large-files-when-the-upl

回答4:

Another simple solution is changing the "\r" instances in the filename path to "\R"

转载请标明出处:Region: IOError: [Errno 22] invalid mode ('w') or filename

文章来源: Region: IOError: [Errno 22] invalid mode ('w') or filename

标签

errno