Python error: “socket.error: [Errno 11] Resource temporarily unavailable” when sending image

匿名 (未验证) 提交于 2019-12-03 02:26:02

问题:

I want to make a program that accesses images from files, encodes them, and sends them to an server. Than the server is supposed to decode the image, and save it to file. I tested the image encoding itself, and it worked, so the problem lies in the server and client connection.

Here is the server:

import socket import errno import base64  from PIL import Image import StringIO  def connect(c):     try:         image = c.recv(8192)         return image     except IOError as e:         if e.errno == errno.EWOULDBLOCK:             connect(c)   def Main():     host = '138.106.180.21'     port = 12345      s = socket.socket(socket.AF_INET, socket.SOCK_STREAM, socket.IPPROTO_TCP)     s.setsockopt(socket.SOL_SOCKET,socket.SO_REUSEADDR,1)     s.bind((host, port))     s.listen(1)       while True:          c, addr = s.accept()         c.setblocking(0)          print "Connection from: " + str(addr)          image = c.recv(8192)#connect(c)          imgname = 'test.png'          fh = open(imgname, "wb")         if image == 'cusdom_image':             with open('images.png', "rb") as imageFile:                 image = ''                 image = base64.b64encode(imageFile.read())                 print image         fh.write(image.decode('base64'))         fh.close()   if __name__ == '__main__':     Main() 

And here is the client:

import socket import base64  from PIL import Image import StringIO import os, sys  ip = '138.106.180.21' port = 12345 print 'Add event executed' s = socket.socket() s.connect((ip, port))  image_path = '/home/gilgamesch/Bilder/Bildschirmfoto.png'  print os.getcwd() olddir = os.getcwd() os.chdir('/') print os.getcwd()  if image_path != '':     with open(image_path, "rb") as imageFile:         image_data = base64.b64encode(imageFile.read())         print 'open worked' else:     image_data = 'cusdom_image'  os.chdir(olddir)  s.send(image_data)   s.close() 

And the error message is:

Traceback (most recent call last):   File "imgserv.py", line 49, in <module>     Main()   File "imgserv.py", line 34, in Main     image = c.recv(8192)#connect(c) socket.error: [Errno 11] Resource temporarily unavailable 

回答1:

In the server you are setting the remote socket (that returned by accept()) to non-blocking mode, which means that I/O on that socket will terminate immediately by an exception if there is no data to read.

There will usually be a period of time between establishing the connection with the server and the image data being sent by the client. The server attempts to immediately read data from the client once the connection is accepted, however, there might not be any data to read yet, so c.recv() raises a socket.error: [Errno 11] Resource temporarily unavailable exception. Errno 11 corresponds to EWOULDBLOCK, so recv() aborted because there was no data ready to read.

Your code does not seem to require non-blocking sockets because there is an accept() at the top of the while loop, and so only one connection can be handled at a time. You can just remove the call to c.setblocking(0) and this problem should go away.



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