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问题:
I can convert a cell array of matrices to matrix:
>> C={[1,1]; [2,2]; [3,3]}; >> cell2mat(C) ans = 1 1 2 2 3 3
This is OK. But, I want to convert a cell array including other cell arrays to a matrix:
>> C={{1,1}; {2,2}; {3,3}}; >> cell2mat(C) Error using cell2mat (line 53) Cannot support cell arrays containing cell arrays or objects.
So, desired output is:
>> mycell2mat({{1,1}; {2,2}; {3,3}}) ans = 1 1 2 2 3 3
How to do this?
Edit:
I want to do same thing for multidimensional ones also:
>> mycell2mat({{1,1;1,1}; {2,2;2,2}; {3,3;3,3}}) ans(:,:,1) = 1 1 1 1 ans(:,:,2) = 2 2 2 2 ans(:,:,3) = 3 3 3 3
回答1:
To be honest, I never liked cell2mat
for being slow, so I've come up an alternative solution using comma-separated lists instead!
Transform a cell array of vectors
This is fairly simple, just use the colon operator and concatenate all vectors vertically:
C = {[1,1]; [2,2]; [3,3]}; A = vertcat(C{:})
and so we get:
A = 1 1 2 2 3 3
Transform a cell array of cell arrays
This is a bit trickier. Since it's a cell array of cell arrays, we'll have to obtain a vector of all elements by a double use of the colon and horzcat
, and then reshape
it into the desired matrix.
C = {{1,1}; {2,2}; {3,3}}; V = [size(C{1}), 1]; V(find(V == 1, 1)) = numel(C); A = reshape([horzcat(C{:}){:}], V)
and so we get:
A = 1 1 2 2 3 3
The manipulation of V
makes sure that A
is reshaped correctly without having to specify the output dimensions explicitly (unfortunately, I didn't find a one liner for this). This also works for multi-dimensional cell arrays as well:
C = {{1, 1; 1, 1}; {2, 2; 2, 2}; {3, 3; 3, 3}}; V = [size(C{1}), 1]; V(find(V == 1, 1)) = numel(C); A = reshape([horzcat(C{:}){:}], V) A(:,:,1) = 1 1 1 1 A(:,:,2) = 2 2 2 2 A(:,:,3) = 3 3 3 3
P.S
I think the correct result for the last example should be a 6-by-2 matrix instead of a 2-by-2-by-3. However, that is not what you requested, so it's off-topic.
回答2:
This should do the trick:
cellOfCells = {{1,1}; {2,2}; {3,3}}; cell2mat(cellfun(@cell2mat, cellOfCells, 'UniformOutput', false))
Edit:
I agree that keeping it simple is an important, but so is having fun :) So - here's a one-liner that should do the trick (and can be easily generalized for any size):
a = {{1,1;1,1}; {2,2;2,2}; {3,3;3,3}} reshape(cell2mat(cellfun(@cell2mat,a, 'UniformOutput', false))', 2, 2, 3)
回答3:
keep it simple
c = {{1,1;1,1}; {2,2;2,2}; {3,3;3,3}}; z = zeros([size(c{1}) size(c,1)]); for i=1:size(c,1) z(:,:,i)=cell2mat(c{i}); end
gives
EDU>> z z(:,:,1) = 1 1 1 1 z(:,:,2) = 2 2 2 2 z(:,:,3) = 3 3 3 3
回答4:
Okay, the question is a long time ago - but maybe my answer might help other readers or searchers.
I think the best solution is nearly the idea presented by Eitan T but it is possible to do that without reshaping. For me
C={{1,1;1,1};{2,2;2,2};{3,3;3,3}}; A=cell2mat(cat(3,C{:}))
does what was asked for - thus answers with
A(:,:,1) = 1 1 1 1 A(:,:,2) = 2 2 2 2 A(:,:,3) = 3 3 3 3
Hoping that helps.
回答5:
I had the same error, I just commented out the lines in cell2mat that return the error and everything work fine to me.
lines to comment out in cell2mat (51:53): (you can find them using dbstop if error)
if cisobj || ciscell error(message('MATLAB:cell2mat:UnsupportedCellContent')); end