MySQL Query to select data from last week?

问题:

Hi I have a table with a date field and some other information. I want to select all entries from the past week, (week start from Sunday).

table values:

id  date 2   2011-05-14 09:17:25 5   2011-05-16 09:17:25 6   2011-05-17 09:17:25 8   2011-05-20 09:17:25 15  2011-05-22 09:17:25

I want to select all ids from last week, expected output is 5, 6, 8. (id 2 not in last week, and id 15 is in current week.)

How to write and SQL Query for the same.

回答1:

SELECT id FROM tbl WHERE date >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY AND date 

回答2:

select id from tbname where date between date_sub(now(),INTERVAL 1 WEEK) and now();

回答3:

Simplified form:

Last week data:

SELECT id FROM tbl   WHERE  WEEK (date) = WEEK( current_date ) - 1 AND YEAR( date) = YEAR( current_date );

2 weeks ago data:

SELECT id FROM tbl   WHERE  WEEK (date) = WEEK( current_date ) - 2 AND YEAR( date) = YEAR( current_date );

SQL Fiddle

http://sqlfiddle.com/#!8/6fa6e/2

回答4:

You can make your calculation in php and then add it to your query:

$date = date('Y-m-d H:i:s',time()-(7*86400)); // 7 days ago  $sql = "SELECT * FROM table WHERE date 

now this will give the date for a week ago

回答5:

SELECT id FROM table1 WHERE YEARWEEK(date) = YEARWEEK(NOW() - INTERVAL 1 WEEK)

I use the YEARWEEK function specifically to go back to the prior whole calendar week (as opposed to 7 days before today). YEARWEEK also allows a second argument that will set the start of the week or determine how the first/last week of the year are handled. YEARWEEK lets you to keep the number of weeks to go back/forward in a single variable, and will not include the same week number from prior/future years, and it's far shorter than most of the other answers on here.

回答6:

You'll need to calc which day relative to today is Sunday in your middleware (php, python, etc.)*

Then,

select id from table where date >= "$sunday-date" + interval 7 DAY

• may be a way to get sunday's date relative to today in MySQL as well; that would be arguably the cleaner solution if not too expensive to perform

回答7:

Probably the most simple way would be:

SELECT id FROM table WHERE date >= current_date - 7

For 8 days (i.e. Monday - Monday)

回答8:

It can be in a single line:

SELECT * FROM table WHERE Date BETWEEN (NOW() - INTERVAL 7 DAY) AND NOW()

回答9:

The above query will not work. After the where clause, if we can not CAST the column value, then it will not work. You should cast the column value.

e.g.:

SELECT..... WHERE CAST( yourDateColumn AS DATE ) > DATEADD( DAY, -7, CAST( GETDATE() AS DATE )

回答10:

SELECT id  FROM tb1 WHERE  YEARWEEK (date) = YEARWEEK( current_date -interval 1 week ) 

回答11:

I often do a quick "last week" check as well and the following tends to work well for me and includes today.

DECLARE @StartDate DATETIME  DECLARE @EndDate DATETIME   SET @StartDate = Getdate() - 7 /* Seven Days Earlier */ SET @EndDate = Getdate() /* Now */  SELECT id  FROM   mytable  WHERE  date BETWEEN @StartDate AND @Enddate 

If you want this to NOT include today just subtract an extra day from the @EndDate. If I select these two variables today get

@StartDate 2015-11-16 16:34:05.347 /* Last Monday */

@EndDate 2015-11-23 16:34:05.347 /* This Monday */

If I wanted Sunday to Sunday I would have the following.

SET @StartDate = Getdate() - 8 /* Eight Days Earlier */ SET @EndDate = Getdate() - 1  /* Yesterday */

@StartDate 2015-11-15 16:34:05.347 /* Previous Sunday */

@EndDate 2015-11-22 16:34:05.347 /* Last Sunday */

回答12:

WHERE yourDateColumn > DATEADD(DAY, -7, GETDATE()) ;

回答13:

You can also use it esay way

SELECT * FROM   inventory WHERE  YEARWEEK(`modify`, 1) = YEARWEEK(CURDATE(), 1)

回答14:

i Use this for the week start from SUNDAY:

SELECT id FROM tbl WHERE date >= curdate() - INTERVAL DAYOFWEEK(curdate())+5 DAY   AND date 

回答15:

A simple way can be this one, this is a real example from my code and works perfectly:

where("actions.created_at >= DATE_SUB(CURDATE(), INTERVAL 1 WEEK)")

回答16:

PLEASE people... 'Last week' like the OP asked and where I was looking for (but found none of answers satisfying) is THE LAST WEEK.

If today is Tuesday, then LAST WEEK is Monday A WEEK AGO to Sunday A WEEK AGO.

So:

WHERE     WEEK(yourdate) = WEEK(NOW()) - 1

Or for ISO weeks:

WHERE     WEEK(yourdate, 3) = WEEK(NOW(), 3) - 1

回答17:

Try this:

Declare @Daytype varchar(15),         @StartDate datetime,         @EndDate datetime set @Daytype = datename(dw, getdate())  if @Daytype= 'Monday'      begin         set @StartDate = getdate()-7          set @EndDate = getdate()-1      end   else if @Daytype = 'Tuesday'      begin         set @StartDate = getdate()-8          set @EndDate = getdate()-2      end Else if @Daytype = 'Wednesday'     begin         set @StartDate = getdate()-9         set @EndDate = getdate()-3     end Else if @Daytype = 'Thursday'     begin         set @StartDate = getdate()-10          set @EndDate = getdate()-4     end  Else if @Daytype = 'Friday'      begin         set @StartDate = getdate()-11         set @EndDate = getdate()-5      end  Else if @Daytype = 'Saturday'      begin         set @StartDate = getdate()-12         set @EndDate = getdate()-6      end  Else if @Daytype = 'Sunday'      begin         set @StartDate = getdate()-13         set @EndDate = getdate()-7      end   select @StartDate,@EndDate

回答18:

If you already know the dates then you can simply use between, like this:

SELECT id     FROM `Mytable`     where MyDate BETWEEN "2011-05-15" AND "2011-05-21"

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