I have a list of excel files with similar last row. It contains private information about client (his name, surname, phone). Each excel file corresponds to a client. I need to make one excel file with all data about every client. I decide to do it automatically, so looked to openpyxl
library. I wrote the following code, but it doesn't work correctly.
import openpyxl import os import glob from openpyxl import load_workbook from openpyxl import Workbook import openpyxl.styles from openpyxl.cell import get_column_letter path_kit = 'prize_input/kit' #creating single document prize_info = Workbook() prize_sheet = prize_info.active file_array_reciever = [] for file in glob.glob(os.path.join(path_kit, '*.xlsx')): file_array_reciever.append(file) row_num = 1 for f in file_array_reciever: f1 = load_workbook(filename=f) sheet = f1.active for col_num in range (3, sheet.max_column): prize_sheet.cell(row=row_num, column=col_num).value = \ sheet.cell(row=sheet.max_row, column=col_num).value prize_info.save("Ex.xlsx")
I get this error:
Traceback (most recent call last): File "/Users/zkid18/PycharmProjects/untitled/excel_test.py", line 43, in <module> f1 = load_workbook(filename=f) File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/site-packages/openpyxl/reader/excel.py", line 183, in load_workbook wb.active = read_workbook_settings(archive.read(ARC_WORKBOOK)) or 0 File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/zipfile.py", line 1229, in read with self.open(name, "r", pwd) as fp: File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/zipfile.py", line 1252, in open zinfo = self.getinfo(name) File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/zipfile.py", line 1196, in getinfo 'There is no item named %r in the archive' % name) KeyError: "There is no item named 'xl/workbook.xml' in the archive"
Looks like it is a problem with reading file.
I don't understand where it gets an item named 'xl/workbook.xml'
in the archive.