Node.js - require empty path

问题:

I came across this file on github, which does this:

var migrate = require('../') 

What does that mean? When I tried the same, I get: Error: Cannot find module '../'

回答1:

It requires the file index.js of the parent folder, which is this one: https://github.com/visionmedia/node-migrate/blob/master/index.js

回答2:

Here is the document from the official node js website. I just put the full steps here, but in terms of your question, find ---- here is what you wanted to know ----

require(X) from module at path Y 1. If X is a core module,    a. return the core module    b. STOP 2. If X begins with './' or '/' or '../'    a. LOAD_AS_FILE(Y + X)    b. LOAD_AS_DIRECTORY(Y + X) 3. LOAD_NODE_MODULES(X, dirname(Y)) 4. THROW "not found"  LOAD_AS_FILE(X) 1. If X is a file, load X as JavaScript text.  STOP 2. If X.js is a file, load X.js as JavaScript text.  STOP 3. If X.json is a file, parse X.json to a JavaScript Object.  STOP 4. If X.node is a file, load X.node as binary addon.  STOP  LOAD_AS_DIRECTORY(X) ---- here is what you wanted to know ---- 1. If X/package.json is a file,    a. Parse X/package.json, and look for "main" field.    b. let M = X + (json main field)    c. LOAD_AS_FILE(M) 2. If X/index.js is a file, load X/index.js as JavaScript text.  STOP 3. If X/index.json is a file, parse X/index.json to a JavaScript object. STOP 4. If X/index.node is a file, load X/index.node as binary addon.  STOP 

More info, please check https://nodejs.org/api/modules.html#modules_all_together

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