I have a class which accepts a pointer to another class and has a method read():
class B: { public: ...... void read(char * str); ...... }; class A { public: A(B *bobj):b(bobj); B* b; void read (char * str); .......... };
I invoke the object like below
A * aobj = new A(new B());
Now I should be able to access read method of both the classes like below:
char text[100]; b->read(text) aobj->read(text)
The method read of both A and B class is coded to copy some values to the input array as provided.
How can I write MOCK method of the function to modify the argument to a specific value?
ON_CALL(*b, read(::testing::_)).WillByDefault(::testing::Return(outBuffer));
Gives me a compilation issue as read method cannot return a value by definition?
I have used Invoke function to achieve this. Here is a sample code.
If you use >=c++11 then, you can simply give a lambda to the Invoke function.
#include <gtest/gtest.h> #include <gmock/gmock.h> using ::testing::Mock; using ::testing::_; using ::testing::Invoke; class actual_reader { public: virtual void read(char* data) { std::cout << "This should not be called" << std::endl; } }; void mock_read_function(char* str) { strcpy(str, "Mocked text"); } class class_under_test { public: void read(actual_reader* obj, char *str) { obj->read(str); } }; class mock_reader : public actual_reader { public: MOCK_METHOD1(read, void(char* str)); }; TEST(test_class_under_test, test_read) { char text[100]; mock_reader mock_obj; class_under_test cut; EXPECT_CALL(mock_obj, read(_)).WillOnce(Invoke(mock_read_function)); cut.read(&mock_obj, text); std::cout << "Output : " << text << std::endl; // Lambda example EXPECT_CALL(mock_obj, read(_)).WillOnce(Invoke( [=](char* str){ strcpy(str, "Mocked text(lambda)"); })); cut.read(&mock_obj, text); std::cout << "Output : " << text << std::endl; }
