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问题:
I have problem with coding 1 app for toomorow lectures.
So, That program ask user for numbers, on typed "100" it's stops, and it shows: -average -min -max
I know what kind of loop, i need to use (do-while right?). But how i'm suppoused to count average,min,max without using arrays ?
回答1:
this is shorthand pseudo code because you have to code this yourself:
min = max = total = user_input count = 0 do { count++ input = get_input total += input min or max maybe = input } while (input !=100) average = total / count print stuff
good luck
回答2:
Step 1 : user three temp variable Step 2 : initialize three temp variable(min,max,avg all by 0) Step 1 : inside the loop if temp > max ==>> max = temp Step 1 : inside the loop if temp < min ==>> min = temp Step 1 : avg = ( avg + temp )/i int[] values = { .. values .. } int min=0,max=0,avg = 0; for(int i=1;i<=values.length;i++) { if(min > values[i]) min = values[i] if(max < values[i]) max = values[i] avg = ( avg + values[i] ) / i }
回答3:
I can tell you how to calculate average min and max without arrays. I cannot, however tell you how to calculate average min and max WITH arrays.
Minimum is easy:
int current_min ArrayList<int> find_min = new ArrayList<int>(); for (int c : find_min) if (c < current_min) current_min = c;
Maximum is a little bit harder. You need to use "functions"
boolean check_if_integer_is_bigger_than_another_integer(int another_integer_to_check_against, int the_original_integer_goes_here_into_this_argument_here) { if (another_integer_to_check_against > the_original_integer_goes_here_into_this_argument_here) return (another_integer_to_check_against > the_original_integer_goes_here_into_this_argument_here) //Important return (another_integer_to_check_against > the_original_integer_goes_here_into_this_argument_here) } int current_max ArrayList<int> find_max = new ArrayList<int>(); for (int c : find_max) if (check_if_integer_is_bigger_than_another_integer(c, current_max)) current_max = c;
I dont even want to go into averaging. You have to add numbers and I'm not exactly qualified for that.