Linux bash script for loop

问题:

i have 1.txt 2.txt and script.php

1.txt: a b c d 2.txt www rrr ttt yyy 

i want bash file to do this command in Linux:

./script.php -n a -j www>>n_j.txt ./script.php -n a -j rrr>>n_j.txt ./script.php -n a -j ttt>>n_j.txt ./script.php -n a -j yyy>>n_j.txt ./script.php -n b -j www>>n_j.txt ./script.php -n b -j rrr>>n_j.txt ./script.php -n b -j ttt>>n_j.txt . . 

i have a bat code working with wondows cmd..i wanna a code like it to work with Linux command line

@ECHO OFF   FOR /F "tokens=1 delims= " %%I IN (1.txt) DO FOR /F "tokens=1 delims= " %%E IN (2.txt) DO echo %%I %%E>n_j.txt & echo name_job: %%I %%E & FOR /F "tokens=*" %%S IN ('script.php -n %%I -j %%E') DO echo %%S>>names\n_j.txt 

回答1:

#!/bin/bash  arr1="" arr2="" mapfile -t arr1 <1.txt mapfile -t arr2 <2.txt  for i in ${!arr1[@]}; do         for j in ${!arr2[@]}; do                 ./script.php -n "${arr1[i]}" -j "${arr2[j]}" >>n_j.txt         done done 

mapfile -t converts the file to an array, where each line of the file is a new index in the array (-t removes the trailing newline). The for loops iterate over each index of the array, the outer loop going through the lines in the first file, the inner loop going through the lines in the second file, calling script.php with the current array indices.

回答2:

Simply pipe the file in while loop, see if this could help.

#!/bin/bash while read arg1 do    while read arg2    do      ./script.php -n $arg1 -j $arg2 >>n_j.txt    done<2.txt done<1.txt 

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