面试：按一定规律生成数组

 a = [1,1,2,3,5,8]

 写一个函数，给定一个参数（正整数），给出a顺序的数组

 def sort_list(num):     a = []     if num == 1:         a = [1]     elif num == 2:         a = [1,1]     else:         a = [1,1]         for i in range(2,num):             b = a[i-1] + a[i-2]             a.append(b)     return a sort = sort_list(3) print(sort)

文章来源: https://blog.csdn.net/u013155359/article/details/91454161