题目链接:http://poj.org/problem?id=3903
最长上升子序列入门题。
算法时间复杂度 O(n*logn)
。
代码:
#include <iostream> #include <algorithm> using namespace std; const int maxn = 100010; int n, a[maxn], f[maxn], maxlen = 0; int main() { while (cin >> n) { maxlen = 0; for (int i = 1; i <= n; i ++) cin >> a[i]; for (int i = 1; i <= n; i ++) { int idx = lower_bound(f, f+maxlen, a[i]) - f; if (idx >= maxlen) { f[maxlen++] = a[i]; } else { f[idx] = a[i]; } } cout << maxlen << endl; } return 0; }