JS 判断是否包含特殊字符

匿名 (未验证) 提交于 2019-12-02 23:26:52
 判断字符中是否包含有特殊字符:      function containSpecial( s )       {           var containSpecial = RegExp(/[(\ )(\~)(\!)(\@)(\#)   (\$)(\%)(\^)(\&)(\*)(\()(\))(\-)(\_)(\+)(\=)   (\[)(\])(\{)(\})(\|)(\\)(\;)(\:)(\')(\")(\,)(\.)(\/)   (\<)(\>)(\?)(\)]+/);           return ( containSpecial.test(s) );       }     

文章来源: https://blog.csdn.net/qq_37383968/article/details/89428354
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