MySql JSON类型 键名有特殊字符

执行以下语句报错：

 SELECT `JsonField`->>'$.#key' FROM tableName;  [Err] 3143 - Invalid JSON path expression. The error is around character position 4.

解决方案，#key加双引号：

 SELECT `JsonField`->>'$."#key"' FROM tableName;

文章来源: https://blog.csdn.net/Nansen_/article/details/97006690