Java发送POST请求，参数为JSON格式，并接收返回JSON数据

原文地址：https://blog.csdn.net/qq_26975307/article/details/82713725/**      * 发送post请求      * @param url  路径      * @param jsonObject  参数(json类型)      * @param encoding 编码格式      * @return      * @throws ParseException      * @throws IOException      */     public static String send(String url, JSONObject jsonObject,String encoding) throws ParseException, IOException{         String body = "";           //创建httpclient对象         CloseableHttpClient client = HttpClients.createDefault();         //创建post方式请求对象         HttpPost httpPost = new HttpPost(url);           //装填参数         StringEntity s = new StringEntity(jsonObject.toString(), "utf-8");         s.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,                 "application/json"));         //设置参数到请求对象中         httpPost.setEntity(s);         System.out.println("请求地址："+url); //        System.out.println("请求参数："+nvps.toString());           //设置header信息         //指定报文头【Content-type】、【User-Agent】 //        httpPost.setHeader("Content-type", "application/x-www-form-urlencoded");         httpPost.setHeader("Content-type", "application/json");         httpPost.setHeader("User-Agent", "Mozilla/4.0 (compatible; MSIE 5.0; Windows NT; DigExt)");           //执行请求操作，并拿到结果（同步阻塞）         CloseableHttpResponse response = client.execute(httpPost);         //获取结果实体         HttpEntity entity = response.getEntity();         if (entity != null) {             //按指定编码转换结果实体为String类型             body = EntityUtils.toString(entity, encoding);         }         EntityUtils.consume(entity);         //释放链接         response.close();         return body;     }

来源：博客园

作者：懒得像猪

链接：https://www.cnblogs.com/wxm-bk/p/11468501.html